Math  /  Algebra

QuestionFind the complex conjugate of 9+9i9+9i and calculate (9+9i)(9+9i)(9+9i)(\overline{9+9i}).

Studdy Solution
Remember that i2=1i^2 = -1. Substitute 1-1 for i2i^2 in the expression.
(9+9i)(99i)=8181(1)=81+81=162(9+9i)(9-9i) =81 -81*(-1) =81 +81 =162So, the complex conjugate of 9+9i9+9i is 99i9-9i and the product of 9+9i9+9i and its conjugate is 162162.

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