Math  /  Data & Statistics

QuestionA simple random sample of size n=200n=200 individuals who are currently employed is asked if they work at home at least once per week. Of the 200 employed individuals surveyed, 29 responded that they did work at home at least once per week. Construct a 99%99 \% confidence interval for the population proportion of employed individuals who work at home at least once per week.
The lower bound is 0.081 . (Round to three decimal places as needed.) The upper bound is \square . (Round to three decimal places as needed.)

Studdy Solution
Determine the confidence interval:
Lower bound: p^ME=0.1450.0642=0.08080.081 \hat{p} - ME = 0.145 - 0.0642 = 0.0808 \approx 0.081
Upper bound: p^+ME=0.145+0.0642=0.2092 \hat{p} + ME = 0.145 + 0.0642 = 0.2092
The upper bound is:
0.209 \boxed{0.209}

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