Math  /  Algebra

QuestionA sealed can of gas has a pressure of 2.0 atm at 300 K . If the can is heated to 600 K , what will the pressure become (assuming constant volume)?

Studdy Solution
Solve for the final pressure P2 P_2 . Cross-multiply to solve for P2 P_2 :
P2=2.0atm×600K300K P_2 = \frac{2.0 \, \text{atm} \times 600 \, \text{K}}{300 \, \text{K}}
Simplify the expression:
P2=1200atmK300K P_2 = \frac{1200 \, \text{atm} \cdot \text{K}}{300 \, \text{K}}
P2=4.0atm P_2 = 4.0 \, \text{atm}
The final pressure of the gas is:
4.0atm \boxed{4.0 \, \text{atm}}

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