QuestionA scientist measures $81.1 \mathrm{~cm}^{3}$; true value is $60.0 \mathrm{~cm}^{3}$. Find absolute and relative error.

Studdy Solution
Calculate the relative error percentage.
$$Relative\, error =.3516666667 \times100\% =35.17\%$$The absolute error of the scientist's measurement is $21. \mathrm{~cm}^{3}$ and the relative error is $35.17\%$.