Math  /  Probability

Question Find the probability that all 3 randomly drawn tickets from a money box with 15 50tickets,1050 tickets, 10 25 tickets, and 10 $5 tickets, plus 20 dummy tickets, have no monetary value.
The probability that all 3 tickets drawn have no money value is 205519541853\frac{20}{55} \cdot \frac{19}{54} \cdot \frac{18}{53}.

Studdy Solution
Calculate the probability that all three tickets drawn have no money value.
(3Dummies)=2055times1954times1853=.0244(3\, Dummies) = \frac{20}{55} \\times \frac{19}{54} \\times \frac{18}{53} =.0244The probability that all three tickets drawn have no money value is .0244.0244.

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