Question Solve the quadratic equation $z^{2} - 13z + 12 = 0$ for real values of $z$.

Studdy Solution
Verify the second root by plugging $z=12$ into the original equation:
$$(12)^2 - 13(12) + 12 = 144 - 156 + 12 = 0$$
The roots of the quadratic polynomial $z^{2}-13z+12$ are $z=1$ and $z=12$.