Math

QuestionA powerful motorcycle can produce an acceleration of 3.50 m/s23.50 \mathrm{~m} / \mathrm{s}^{2} while traveling at 90.0 km/h90.0 \mathrm{~km} / \mathrm{h}. At that speed, the forces resisting motion, including frictio and air resistance, total 400.0 N . (Air resistance is analogous to air friction. It always opposes the motion of an object.) What is the magnitude of the fo that motorcycle exerts backward on the.ground to produce its acceleration if the mass of the motorcycle with rider is 245 kg ?

Studdy Solution
Calculate the magnitude of the force the motorcycle exerts backward on the ground:
Ftotal=857.5N+400.0N F_{\text{total}} = 857.5 \, \mathrm{N} + 400.0 \, \mathrm{N}
Ftotal=1257.5N F_{\text{total}} = 1257.5 \, \mathrm{N}
The magnitude of the force that the motorcycle exerts backward on the ground is:
1257.5N \boxed{1257.5 \, \mathrm{N}}

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