QuestionA point moves along the circle $x^{2}+y^{2}=25$ so that $\frac{\mathrm{d} x}{\mathrm{~d} t}=2 \mathrm{~cm} / \mathrm{min}$. Find $\frac{\mathrm{d} y}{\mathrm{~d} t}$ at the point $(-2, \sqrt{21})$ Use the sqrt function or an exponent of $1 / 2$ to represent a square root in your answer. For example to write $\sqrt{5}$ you should either enter $5^{\wedge}(1 / 2)$ or sqrt(5). Also, don't forget to use * to represent any multiplication.
Numeric part Units