Math  /  Math Statement

QuestionA nickel absorbs 74 J74 \mathrm{~J} from water cooling from 65.5C65.5^{\circ} \mathrm{C} to 63.4C63.4^{\circ} \mathrm{C}. Find mass of water: CH2O=4.18JgC, mH2O=[?]g\mathrm{C}_{\mathrm{H}_{2} \mathrm{O}}=4.18 \frac{\mathrm{J}}{\mathrm{g} \cdot{ }^{\circ} \mathrm{C}}, \mathrm{~m}_{\mathrm{H}_{2} \mathrm{O}}=[?] \mathrm{g}

Studdy Solution
Calculate the mass of the water.
mH2=74J4.18Jg°C2.1°C8.43gm_{H2} = \frac{74 J}{4.18 \frac{J}{g \cdot °C} \cdot2.1°C} \approx8.43 gThe mass of the water that was cooled is approximately8.43 g.

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