QuestionA metal was heated and placed in 100.0 mL of water at 21.2°C, reaching 32.0°C. Find the energy absorbed by the water. $$\mathrm{C}_{\mathrm{H}_{2} \mathrm{O}}=4.18 \frac{\mathrm{J}}{\mathrm{g} \cdot{ }^{\circ} \mathrm{C}} \\ \mathrm{q}_{\mathrm{H}_{2} \mathrm{O}}=[?] \mathrm{J}$$