Math  /  Word Problems

QuestionHow much energy did 100.0 mL of water absorb when heated from 23.7°C to 27.8°C? Use CH2O=4.18JgC\mathrm{C}_{\mathrm{H}_{2} \mathrm{O}}=4.18 \frac{\mathrm{J}}{\mathrm{g} \cdot{ }^{\circ} \mathrm{C}}.

Studdy Solution
Calculate the heat energy absorbed by the water.
Q=100.0g4.18JgC4.C=1714.18JQ =100.0\, g \cdot4.18\, \frac{J}{g \cdot ^{\circ}C} \cdot4.\, ^{\circ}C =1714.18\, JThe water absorbed1714.18 Joules of energy.

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