QuestionFind the center of mass for a man (80 kg), woman (65 kg), and canoe (40 kg) at $x=0$ and $x=6$. Then, if the man moves to the center and the woman moves 1/3 of the canoe's length, how far does the canoe move? Answer in meters.

Studdy Solution
The canoe moves in the water such that the center of mass of the system remains the same. Therefore, the distance the canoe moves is the difference between the new and the old center of mass.
$$\Delta x = x_{cm_{new}} - x_{cm_{old}} =3.35\, m -2.76\, m =.59\, m$$So, the canoe moves approximately.59 m in the water.