QuestionFind the secant line for $f(x)=\frac{5}{x}$ between $x=4$ and $x=5$, and the tangent line at $x=4$.

Studdy Solution
Now we can write the equation of the tangent line as $y = m_{tan}x + b$.
$$y = -\frac{5}{16}x +.75$$The equation of the secant line is $y = -0.25x +2.25$ and the equation of the tangent line is $y = -\frac{5}{16}x +.75$.