Math  /  Word Problems

QuestionA cylinder holds 1.20 L1.20 \mathrm{~L} of gas at 45.0 atm and 314 K314 \mathrm{~K}. What is the new volume at 96.0 atm and 420 K420 \mathrm{~K}?

Studdy Solution
Perform the multiplication and division to find the new volumeV2=(45.0×1.20×420)/(96.0×314)0.71V2 = (45.0 \times1.20 \times420) / (96.0 \times314) \approx0.71\, \mathrm{}The new volume of the cylinder is approximately0.71 L.

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