QuestionCalculate the centripetal acceleration at Earth's equator ($r = 6,371 \text{ km}$) and find the period for $9.8 \text{ m/s}^2$.

Studdy Solution
Calculate the period in minutes.
$$\approx84.4 \, minutes$$a. The centripetal acceleration of a point on the surface of the Earth at the equator caused by the rotation of the Earth about its axis is approximately $0.0337 \, m/s^2$. b. The period that results in the centripetal acceleration being equal to $9.8 \, m/s^2$ is approximately $84.4$ minutes.