QuestionA basketball player jumps to $1.1 \mathrm{~m}$. What is his hang time in the air before landing?

Studdy Solution
Calculate the total "hang time":
$$Hang\, time =2 \cdot0.475 \mathrm{~s} =0.95 \mathrm{~s}$$The basketball player's "hang time" is approximately0.95 seconds.