Math  /  Algebra

QuestionA ball is thrown upward and outward from a height of 5 feet. The height f(x)=0.1x2+0.6x+5f(x) = -0.1x^2 + 0.6x + 5, where xx is the horizontal distance. Find the maximum height and where it occurs.

Studdy Solution
Calculate the maximum height of the ball.
f(xvertex)=0.1(3)2+0.6(3)+5=5.f(x_{vertex}) = -0.1(3)^{2}+0.6(3)+5 =5.The maximum height of the ball is5. feet, which occurs3 feet from the point of release.

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