QuestionA bacterium triples every hour. Start with 90. Find the count at hour 5 using $a(n)=90 \cdot 3^{n-1}$. Options: A. 21,870 B. 810 C. 7290 D. 1350

Studdy Solution
Calculate the number of bacteria at the beginning of hour5.
$$a(5)=90 \cdot81 =7290$$So, there will be7290 bacteria at the beginning of hour5.