Math  /  Algebra

QuestionA 70 N block and a 35 N block are connected by a massless string as shown in the Figure. If the pulley is massless-frictionless and the surface is frictionless, the magnitude of the acceleration of the 35N35-\mathrm{N} block is (g=10 m/s2)\left(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2}\right)
Select one: a. 1.7 m/s21.7 \mathrm{~m} / \mathrm{s}^{2} b. 3.3 m/s23.3 \mathrm{~m} / \mathrm{s}^{2} c. 9.8 m/s29.8 \mathrm{~m} / \mathrm{s}^{2} d. 4.9 m/s24.9 \mathrm{~m} / \mathrm{s}^{2}

Studdy Solution
Review the calculations. The correct acceleration value should be checked against the given options.
Given options are: a. 1.7 m/s21.7 \mathrm{~m} / \mathrm{s}^{2} b. 3.3 m/s23.3 \mathrm{~m} / \mathrm{s}^{2} c. 9.8 m/s29.8 \mathrm{~m} / \mathrm{s}^{2} d. 4.9 m/s24.9 \mathrm{~m} / \mathrm{s}^{2}
Since 7010.5=6.67\frac{70}{10.5} = 6.67 does not match any of the options, let's review possible errors and assumptions.
Rechecking:
70T=7a    703.5a=7a    70=10.5a    a=7010.56.67 m/s2 70 - T = 7a \implies 70 - 3.5a = 7a \implies 70 = 10.5a \implies a = \frac{70}{10.5} \approx 6.67 \text{ m/s}^2
This value should be correct.
Explanation: Reviewing the problem constraints and calculations, the closest answer is not in the options provided. The correct answer based on the calculation should be 6.67 m/s26.67 \mathrm{~m} / \mathrm{s}^{2}.

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