Math  /  Algebra

Question(a) 32×3x=813^{-2} \times 3^{x}=81
Find the value of xx. 32×3x=3432×3x3^{-2} \times 3^{x}=3^{4} \quad 3^{-2} \times 3^{x} (x)=4(x)=4 422\frac{4}{2} 2 (b) x13=32x2x^{-\frac{1}{3}}=32 x^{-2} 32+343=3\begin{array}{c} 3^{-2}+3^{4}-3 \\ =3 \end{array}
Find the value of xx.

Studdy Solution
For the first equation, x=6x = \textbf{6}.
For the second equation, x=8x = \textbf{8}.

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