Math  /  Algebra

QuestionA 0.750 kg object vibrates at the end of a horizontal spring ( k =995 N/m=995 \mathrm{~N} / \mathrm{m} ) along a frictionless surface. The speed of the object is 2.50 m/s2.50 \mathrm{~m} / \mathrm{s} when its displacement is 0.145 m . What is the maximum displacement of the object?

Studdy Solution
Solve for the maximum displacement A A .
12.8024375=12×995×A2 12.8024375 = \frac{1}{2} \times 995 \times A^2
A2=12.8024375×2995 A^2 = \frac{12.8024375 \times 2}{995}
A2=25.604875995 A^2 = \frac{25.604875}{995}
A2=0.025735 A^2 = 0.025735
A=0.025735 A = \sqrt{0.025735}
A0.1604m A \approx 0.1604 \, \text{m}
The maximum displacement of the object is:
0.1604m \boxed{0.1604 \, \text{m}}

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