Math  /  Data & Statistics

Question9. Complete the table of values for this circuit: \begin{tabular}{|c|c|c|c|c|} \hline & R1R_{1} & R2R_{2} & R3R_{3} & Total \\ \hline U,V\mathrm{U}, \mathrm{V} & 1,78 & 1,78 & 10,22 & 12 \\ \hline I,mA\mathrm{I}, \mathrm{mA} & 8 & 13,75 & & 21,75 \\ \hline R & 220Ω220 \Omega & 130Ω130 \Omega & 470Ω470 \Omega & 551,7Ω551,7 \Omega \\ \hline P mV & & & & \\ \hline \end{tabular}

Studdy Solution
Calculate the power (P P ) for each resistor using P=VI P = VI .
For R1 R_1 :
P1=U1×I1=1.78V×8mA=14.24mW P_1 = U_1 \times I_1 = 1.78 \, \text{V} \times 8 \, \text{mA} = 14.24 \, \text{mW}
For R2 R_2 :
P2=U2×I2=1.78V×13.75mA=24.475mW P_2 = U_2 \times I_2 = 1.78 \, \text{V} \times 13.75 \, \text{mA} = 24.475 \, \text{mW}
For R3 R_3 :
P3=U3×I3=10.22V×0mA=0mW P_3 = U_3 \times I_3 = 10.22 \, \text{V} \times 0 \, \text{mA} = 0 \, \text{mW}
Total Power:
PTotal=UTotal×ITotal=12V×21.75mA=261mW P_{\text{Total}} = U_{\text{Total}} \times I_{\text{Total}} = 12 \, \text{V} \times 21.75 \, \text{mA} = 261 \, \text{mW}
The completed table of values is:
\begin{tabular}{|c|c|c|c|c|} \hline & R_{1} & R_{2} & R_{3} & Total \\ \hline \mathrm{U}, \mathrm{V} & 1.78 & 1.78 & 10.22 & 12 \\ \hline \mathrm{I}, \mathrm{mA} & 8 & 13.75 & 0 & 21.75 \\ \hline R & 220 \Omega & 130 \Omega & 470 \Omega & 551.7 \Omega \\ \hline P mV & 14.24 & 24.475 & 0 & 261 \\ \hline \end{tabular}

View Full Solution - Free
Was this helpful?

Studdy solves anything!

banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ParentsInfluencer programContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord