Math  /  Algebra

Question86 FUNCTIONS (Chapter 3) 11 Suppose f(x)=1xf(x)=\sqrt{1-x} and g(x)=x2g(x)=x^{2}. Find: a (fg)(x)(f \circ g)(x) b the domain and range of (fg)(x)(f \circ g)(x).

Studdy Solution
Determine the range of (fg)(x)=1x2 (f \circ g)(x) = \sqrt{1 - x^2} .
The expression 1x2 \sqrt{1 - x^2} represents the upper half of a circle with radius 1 centered at the origin. The values of 1x2 \sqrt{1 - x^2} range from 0 to 1 as x x varies from 1-1 to 11.
Thus, the range of (fg)(x) (f \circ g)(x) is:
[0,1] [0, 1]
The expression for (fg)(x) (f \circ g)(x) is 1x2 \sqrt{1 - x^2} , with domain [1,1][-1, 1] and range [0,1][0, 1].

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