Question$\int 8 x \cos \left(4 x^{2}+3\right) d x$

Studdy Solution
Substitute back the original variable $x$ using $u = 4x^2 + 3$:
$$\sin(u) + C = \sin(4x^2 + 3) + C$$
The solution to the integral is:
$$\boxed{\sin(4x^2 + 3) + C}$$