Math  /  Algebra

Question(7) If log4(12)=x\log _{4}\left(\frac{1}{2}\right)=x, then the value of xx equal : a. 2 c. 0.25 b. 0.5 (d.) -0.5 (8) If y=3ax+3y=3 a x+3 and y=x121y=\frac{-x}{12}-1 are two perpendicular lines, then the value of aa is: (a) 4 3a1+12=t3 a \cdot \frac{1+}{12}=t^{\prime} b. -4 c. 0.25 d. -0.25

Studdy Solution
بما أن الخطين متعامدين، فإن حاصل ضرب ميولهما يجب أن يكون 1-1:
3a(112)=1 3a \cdot \left(-\frac{1}{12}\right) = -1
3a12=1 -\frac{3a}{12} = -1
تبسيط المعادلة:
3a12=1 \frac{3a}{12} = 1
3a=12 3a = 12
a=123 a = \frac{12}{3}
a=4 a = 4
القيمة الصحيحة لـ xx هي:
0.5 \boxed{-0.5}
والقيمة الصحيحة لـ aa هي:
4 \boxed{4}

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