Math

Question7 Beam ABCD is simply supported at A&D\mathrm{A} \& \mathrm{D} and is continuous over B&C\mathrm{B} \& \mathrm{C}. Determine distribution factors. (AB=BC=CD=6 m)(IAB=I,IBC=2I(\mathrm{AB}=\mathrm{BC}=\mathrm{CD}=6 \mathrm{~m})(\mathrm{IAB}=\mathrm{I}, \mathrm{IBC}=2 \mathrm{I}, ICD=1.5I\mathrm{ICD}=1.5 \mathrm{I} ),

Studdy Solution
The distribution factors are: DFBA=311DF_{BA} = \frac{3}{11}, DFBC=811DF_{BC} = \frac{8}{11}, DFCB=1625DF_{CB} = \frac{16}{25}, and DFCD=925DF_{CD} = \frac{9}{25}.

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