Math  /  Numbers & Operations

Question650 Hz2=3(343 ms343+11mss)650 \mathrm{~Hz}_{2}=3\left(\frac{343 \mathrm{~ms}}{343+11 \mathrm{mss}}\right)

Studdy Solution
Simplify the fraction if possible:
10293542.906 \frac{1029}{354} \approx 2.906
The result of the expression 3(343ms343+11ms) 3 \left( \frac{343 \, \text{ms}}{343 + 11 \, \text{ms}} \right) is approximately 2.906 2.906 , which does not equal 650Hz 650 \, \text{Hz} . Therefore, the equation as given does not hold true.

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