Math  /  Data & Statistics

Question6.156 Juvenile Diabetes Treatment Exercise 2.22 introduces a study examining the effectiveness of the drug teplizumab at delaying or preventing the onset of juvenile diabetes (also called Type 1 diabetes). The results are shown in Table 6.4. a. Using pundefined1\widehat{p}_{1} to represent the proportion in the control group who developed diabetes and pundefined2\widehat{p}_{2} to represent the proportion in the teplizumab group who developed diabetes, find the sample difference in proportions, pundefined1pundefined2\widehat{p}_{1}-\widehat{p}_{2}. b. Find a 99%99 \% confidence interval for the difference in proportions p1p2p_{1}-p_{2}. c. What is the best estimate for the difference in proportions? What is the margin of error for this estimate? d. Can we be confident, at the 99%99 \% level, that the new drug teplizumab is more effective than the control?
TABLE 6.4 Juvenile diabetes treatment \begin{tabular}{|l|c|c|c|} \hline & Diabetes & No diabetes & Total \\ \hline Teplizumab & 16 & 22 & 38 \\ \hline Control & 26 & 12 & 38 \\ \hline Total & 42 & 34 & 76 \\ \hline \end{tabular}

Studdy Solution
The 99% confidence interval for the difference in proportions is (0.020,0.546)(-0.020, 0.546).
The best estimate for the difference is 0.263, with a margin of error of 0.283.
We cannot be 99% confident that teplizumab is more effective than the control.

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