Math  /  Algebra

Question6.02 EXAM REVIEW_UNIT 2 XEM OZ6 Q Find une value of X In the equarinn novow. Question o 6/16 1/6(36x12)5x=101 / 6(36 x-12)-5 x=10
A x=2x=-2 B x=8x=8 C x=12\mathrm{x}=12 D x=22x=22

Studdy Solution
Isolate x x by adding 2 to both sides of the equation:
x2+2=10+2 x - 2 + 2 = 10 + 2 x=12 x = 12
The value of x x is:
12 \boxed{12}

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