Math  /  Calculus

Question6. Find the points on the given curves where the tangent is horizontal or vertical. Check your answers with your grapher. (a) x=10t2,y=t312tx=10-t^{2}, \quad y=t^{3}-12 t (b) x=secθ,y=tanθx=\sec \theta, \quad y=\tan \theta

Studdy Solution
Verify results using a grapher.
The points with horizontal tangents for part (a) are (6,16)(6, -16) and (6,20)(6, 20), and the point with a vertical tangent is (10,0)(10, 0). For part (b), there are no horizontal tangents, and the points with vertical tangents are (1,0)(1, 0) and (1,0)(-1, 0).

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