Math  /  Calculus

Question(6) An integrating factor that makes the differential equation xy2dx+(xyy)dy=0,x>1x y^{2} d x+(x y-y) d y=0, \quad x>1 exact is (a) xe2xx \mathrm{e}^{2 x} (b) (x1)e2x(x-1) \mathrm{e}^{2 x} (c) e2xe^{2 x} (d) (x+1)3e2x(x+1)^{-3} e^{2 x} (e) (x1)e2x(x-1) e^{-2 x}

Studdy Solution
The correct integrating factor, after re-evaluation and considering potential simplifications, is option (c) e2xe^{2x}.

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