Math  /  Geometry

Question5.4 Systems of Nonlinear Equations in Two Variables Question 16 of 16 (2 points) I Question Attempt: 1 of Unlimited 4 5 6 7 8 9 10 11 12 13 14 15
Find the dimensions of a rectangle whose perimeter is 48 m and whose area is 140 m2140 \mathrm{~m}^{2}. Give the answer in simplest form.
The rectangle is \square m by \square m.

Studdy Solution
Verify the solution:
1. Check the perimeter: $ 2(14) + 2(10) = 28 + 20 = 48 \]
2. Check the area: $ 14 \times 10 = 140 \]
Both conditions are satisfied.
The dimensions of the rectangle are 14 14 m by 10 10 m.

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