Math  /  Calculus

Question5xy+ex+y=4-5 \cdot x \cdot y+e^{x+y}=4 a. Find dy dx\frac{\mathrm{d} y}{\mathrm{~d} x} in terms of xx and yy. dy dx=\frac{\mathrm{d} y}{\mathrm{~d} x}= aba^{b} sin(a)\sin (a) xf\frac{\partial}{\partial x} f : \infty α\alpha Ω\Omega 5yex+yex+y5x\frac{5 y-e^{x+y}}{e^{x+y}-5 x} b. Find the value of dydx\frac{d y}{d x} at the point P(5,5)P(\sqrt{5},-\sqrt{5}). dy dx(5,5)=\left.\frac{\mathrm{d} y}{\mathrm{~d} x}\right|_{(\sqrt{5},-\sqrt{5})}=

Studdy Solution
a. dy dx=5yex+yex+y5x\frac{\mathrm{d} y}{\mathrm{~d} x} = \frac{5y - e^{x+y}}{e^{x+y} - 5x} b. dy dx(5,5)=551155\left.\frac{\mathrm{d} y}{\mathrm{~d} x}\right|_{(\sqrt{5},-\sqrt{5})} = \frac{-5\sqrt{5} - 1}{1 - 5\sqrt{5}}

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