Math  /  Algebra

Question5xy+2z=44x+9y5z=122x5y+z=2\begin{array}{l}-5 x-y+2 z=4 \\ 4 x+9 y-5 z=-12 \\ 2 x-5 y+z=2\end{array}

Studdy Solution
Verify the solution by substituting x=1x = 1, y=1y = 1, z=5z = 5 into the original equations:
Equation 1: 5(1)1+2(5)=4-5(1) - 1 + 2(5) = 4
51+10=4 -5 - 1 + 10 = 4
4=4 4 = 4 (True)
Equation 2: 4(1)+9(1)5(5)=124(1) + 9(1) - 5(5) = -12
4+925=12 4 + 9 - 25 = -12
12=12 -12 = -12 (True)
Equation 3: 2(1)5(1)+5=22(1) - 5(1) + 5 = 2
25+5=2 2 - 5 + 5 = 2
2=2 2 = 2 (True)
The solution is verified: x=1x = 1, y=1y = 1, z=5z = 5.
The solution is (x,y,z)=(1,1,5) \boxed{(x, y, z) = (1, 1, 5)} .

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