Math  /  Data & Statistics

Question5. Let XX be a random variable from an exponential distribution with parameter 3. Calculate the variance of variable Z=3X4Z=3 X-4. Is variable Y=2XY=\frac{2}{X} continuous? If yes, find the density.

Studdy Solution
Podstawiamy λ=3\lambda = 3 i upraszczamy:
fY(y)=3e6/y2y2=6y2e6/y f_Y(y) = 3 e^{-6/y} \cdot \frac{2}{y^2} = \frac{6}{y^2} e^{-6/y}
Dla y>0y > 0, to jest gęstość zmiennej YY.
Wariancja zmiennej ZZ wynosi 1. Zmienna YY jest ciągła, a jej gęstość to fY(y)=6y2e6/yf_Y(y) = \frac{6}{y^2} e^{-6/y} dla y>0y > 0.

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