Math  /  Algebra

Question41.0 kg of water per second flows through the cooling system of a diesel engine. The difference between the temperatures of the incoming and outgoing water is 5.0 K . How much energy is being removed each second?

Studdy Solution
Calculate the energy removed per second:
Q=41.04,1865.0 Q = 41.0 \cdot 4,186 \cdot 5.0
Q=858,230J/s Q = 858,230 \, \text{J/s}
Thus, the energy being removed each second is:
858,230J/s \boxed{858,230 \, \text{J/s}}

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