Question4. Assuming that $\operatorname{gcd}(a, b)=1$, prove the following: (b) $\operatorname{gcd}(2 a+b, a+2 b)=1$ or 3 .

Studdy Solution
Since $d$ divides $3$, the possible values for $d$ are $1$ or $3$.
Therefore, we have shown that $\operatorname{gcd}(2a + b, a + 2b) = 1$ or $3$.