Math  /  Calculus

Question4. (15 pts) List the open intervals where the following function is concave up and concave down and list the infection points, if any. (**unit circle on page 9 of exam) f(x)=sin(x)+cos(x),[0,2π]f(x)=\sin (x)+\cos (x),[0,2 \pi]

Studdy Solution
f(x)f(x) is concave up on the interval (3π4,7π4)(\frac{3\pi}{4}, \frac{7\pi}{4}) and concave down on the intervals [0,3π4)[0, \frac{3\pi}{4}) and (7π4,2π](\frac{7\pi}{4}, 2\pi].
The inflection points are at x=3π4x = \frac{3\pi}{4} and x=7π4x = \frac{7\pi}{4}.

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