Question35. The driver in the previous problem applies the brakes when the car is moving at $90.0 \mathrm{~km} / \mathrm{h}$, and the car comes to rest after traveling 40.0 m . What is the net force on the car during its deceleration?
36. An $80.0-\mathrm{kg}$ passenger in an SUV traveling at $1.00 \times 10^{2} \mathrm{~km} / \mathrm{h}$ is wearing a seat belt. The driver slams on the brakes and the SUV stops in 45.0 m . Find th force of the seat belt on the passenger.

Studdy Solution
Use Newton's second law to find the net force.
For problem 35: Let $m$ be the mass of the car. The net force $F$ is given by: $$F = ma$$ Since the mass $m$ is not provided, the net force is expressed in terms of $m$: $$F = m \times (-7.81) \, \text{N}$$
For problem 36: The force of the seat belt $F$ on the passenger is given by: $$F = ma$$ where $m = 80.0 \, \text{kg}$ and $a = -8.576 \, \text{m/s}^2$.
$$F = 80.0 \times (-8.576)$$ $$F = -686.08 \, \text{N}$$
The force of the seat belt on the passenger is $\boxed{-686.08 \, \text{N}}$.