Math  /  Geometry

QuestionIn triangle ABCABC, with points DD on ABAB and EE on BCBC, find angles given ABC=28\angle ABC=28^{\circ}, BED=38\angle BED=38^{\circ}.
(a) Find ACD\angle ACD. (b) Express DFE\angle DFE in terms of θ\theta where CAE=θ\angle CAE=\theta.

Studdy Solution
Therefore, DFE=142θ\angle DFE =142^\circ - \theta.
(a) ACD=266\angle ACD =266^\circ. (b) DFE=142θ\angle DFE =142^\circ - \theta.

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