Question$3 x^{3}-4 x^{2}-17 x+6=0$

Studdy Solution
Verify all solutions $x = -2$, $x = 3$, and $x = \frac{1}{3}$ by substituting back into the original equation $3x^3 - 4x^2 - 17x + 6 = 0$.
Solution: The roots of the equation $3x^3 - 4x^2 - 17x + 6 = 0$ are: $x = -2, \quad x = 3, \quad x = \frac{1}{3}$