Math  /  Calculus

Question3. n=15n3n4+7\sum_{n=1}^{\infty} \frac{5 n^{3}}{n^{4}+7}

Studdy Solution
Determine the convergence or divergence of the original series. Since the harmonic series n=11n\sum_{n=1}^{\infty} \frac{1}{n} diverges and the Limit Comparison Test shows that our series behaves like the harmonic series, the original series n=15n3n4+7\sum_{n=1}^{\infty} \frac{5n^3}{n^4+7} also diverges.
The series n=15n3n4+7\sum_{n=1}^{\infty} \frac{5n^3}{n^4+7} diverges.

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