Math  /  Trigonometry

Question3) Dado cosα=32\cos \alpha=\frac{\sqrt{3}}{2}, calcular Sen 2α,Cos2α,Tg2α2 \alpha, \operatorname{Cos} 2 \alpha, \operatorname{Tg} 2 \alpha

Studdy Solution
Calculate tan2α\tan 2\alpha:
tan2α=3\tan 2\alpha = \sqrt{3}
The values are: - sin2α=32\sin 2\alpha = \frac{\sqrt{3}}{2} - cos2α=12\cos 2\alpha = \frac{1}{2} - tan2α=3\tan 2\alpha = \sqrt{3}

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