Math / GeometryQuestion22. x=x=x= \qquad m∠ABD=m \angle A B D=m∠ABD= \qquad m∠DBC=m \angle D B C=m∠DBC= \qquadStuddy SolutionSimplify m∠DBC m \angle DBC m∠DBC:m∠DBC=162019−11=1620−20919=141119 m \angle DBC = \frac{1620}{19} - 11 = \frac{1620 - 209}{19} = \frac{1411}{19} m∠DBC=191620−11=191620−209=191411Therefore, the solutions are: x=18019,m∠ABD=200919∘,m∠DBC=141119∘ x = \frac{180}{19}, \quad m \angle ABD = \frac{2009}{19}^\circ, \quad m \angle DBC = \frac{1411}{19}^\circ x=19180,m∠ABD=192009∘,m∠DBC=191411∘View Full Solution - FreeWas this helpful?
