Math  /  Algebra

Question22. If f(x)=11+xf(x)=\frac{1}{1+x} and g(x)=12+xg(x)=\frac{1}{2+x}, determine f(g(x))f(g(x)).

Studdy Solution
Simplify the expression 11+12+x \frac{1}{1 + \frac{1}{2+x}} . To do this, we need to simplify the denominator:
1. Start with the expression inside the denominator: 1+12+x 1 + \frac{1}{2+x} .
2. Find a common denominator for the terms in the denominator:

1+12+x=(2+x)(2+x)+12+x=(2+x)+12+x=3+x2+x 1 + \frac{1}{2+x} = \frac{(2+x)}{(2+x)} + \frac{1}{2+x} = \frac{(2+x) + 1}{2+x} = \frac{3+x}{2+x}
3. Substitute back into the main expression:
f(g(x))=13+x2+x f(g(x)) = \frac{1}{\frac{3+x}{2+x}}
4. Simplify by taking the reciprocal of the fraction in the denominator:
f(g(x))=2+x3+x f(g(x)) = \frac{2+x}{3+x}
The expression for f(g(x)) f(g(x)) is 2+x3+x \boxed{\frac{2+x}{3+x}} .

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