Math / Calculus

Question21 Mark for Review 420
Let $f$ be the function defined by $f(x)=12 x-x^{3}$ . What is the absolute minimum value of $f$ on the closed interval $[0,3]$ ? (A) -16 (B) 0 (C) 9 (D) 16

Studdy Solution
Compare the values to find the absolute minimum:
- $f(0) = 0$ - $f(2) = 16$ - $f(3) = 9$
The absolute minimum value is $\boxed{0}$ .

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