Math  /  Geometry

QuestionABCD\square A B C D 中, AC,BDA C, B D 交于点 OO, 点 E,FE, FACA C 上, AE=CFA E=C F。证明四边形 EBFDE B F D 是平行四边形和菱形。

Studdy Solution
Since ED=FDED = FD and we have already proven that EB=FBEB = FB, we can say that EBFDEBFD is a rhombus because all sides are equal.
The quadrilateral EBFDEBFD is a parallelogram and if BAC=DAC\angle BAC = \angle DAC, then EBFDEBFD is a rhombus.

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