Math  /  Algebra

Question20) Déterminez la règle de chaque fonction. b) a) a<0f(x)=axh+kf(x)=ax+8+4h,k(8,4)3=a2+8+4p(3,3)1a=3+8aa8a=5f(x)=5x+8+4\begin{array}{ll} a<0 & f(x)=\frac{a}{x-h}+k \quad f(x)=\frac{a}{x+8}+4 \\ h, k \rightarrow(-8,4) & 3=\frac{a}{-2+8}+4 \\ p(-3,3) & -1 \cdot a=-3+8 \\ a & a-8 \\ & a=-5 \\ f(x) & =\frac{-5}{x+8}+4 \end{array} 114 CHAPITRE 2 MÉll-MÉlo

Studdy Solution
L'équation de la fonction est f(x)=6x+8+4f(x) = \frac{-6}{x + 8} + 4.

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