Math  /  Algebra

Question20 Celia and Anson had $2550\$ 2550 altogether. After Celia spent 35\frac{3}{5} of her money and Anson spent $730\$ 730, they had the same amount of money left. How much money did Anson have at first? \ \qquad$

Studdy Solution
Solve the equations to find Anson's initial amount.
First, solve for C C from the first equation: C=2550A C = 2550 - A
Substitute C=2550A C = 2550 - A into the second equation: 25(2550A)=A730 \frac{2}{5}(2550 - A) = A - 730
Distribute the 25\frac{2}{5}: 25×255025A=A730 \frac{2}{5} \times 2550 - \frac{2}{5}A = A - 730
Calculate 25×2550\frac{2}{5} \times 2550: 102025A=A730 1020 - \frac{2}{5}A = A - 730
Combine like terms: 1020+730=A+25A 1020 + 730 = A + \frac{2}{5}A
1750=75A 1750 = \frac{7}{5}A
Solve for A A by multiplying both sides by 57\frac{5}{7}: A=1750×57 A = 1750 \times \frac{5}{7}
Calculate: A=1250 A = 1250
Anson initially had: 1250 \boxed{1250}

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