Question2. Suppose two children push horizontally, but in exactly opposite directions, on a third child in a wagon. The first child exerts a force of 75.0 N , the second exerts a force of 90.0 N , friction is 12.0 N , and the mass of the third child plus wagon is 23.0 kg . (a) What is the system of interest if the acceleration of the child in the wagon is to be calculated? (See the free-body diagram.) (b) Calculate the acceleration. (c) What would the acceleration be if friction were 15.0 N ?

Studdy Solution
Recalculate the acceleration with a different friction force.
If the friction force is 15.0 N, the net force becomes:
$F_{\text{net}} = 90.0 \, \text{N} - 75.0 \, \text{N} - 15.0 \, \text{N}$
$F_{\text{net}} = 0.0 \, \text{N}$
Since the net force is zero, the acceleration is:
$a = \frac{0.0 \, \text{N}}{23.0 \, \text{kg}}$
$a = 0.0 \, \text{m/s}^2$

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